Miracle Learning Center
Boron Nitride – An Overview

09 May Boron Nitride – An Overview

Learning Chemistry at Miracle Learning Centre is a very exciting experience which is filled with fun and knowledge at every step. Our classes are innovative, modernized and result oriented. Various students looking for O level chemistry tuition, a level chemistry tuition, JC chemistry tuition have come to our center and have felt the difference. Our classes conducted by the best chemistry teachers of Singapore are focused to clear all the doubts of the students by giving them in-depth, step by step knowledge at every point.

There are some topics in Chemistry which the students feel difficulty to understand. Today we are talking about Boron Nitride. Boron Nitride is a compound of Boron and Nitrogen which is thermally and chemically resistant. It remains in numerous crystalline forms which are isoelectronic to a similar carbon lattice.

Because of the excellent thermal and chemical stability, boron nitride ceramics are mainly used as parts of high-temperature equipment.

Re-evaluate your knowledge and skills by solving these questions based on Boron Nitride.

5 .        Boron nitride, BN, exists in two physical forms. The structures of these forms are shown below.

chemistry_tuition_q

These two forms of boron nitride resemble two allotropes of carbon.

 

(a)        Suggest why boron nitride with structure A can be used as a lubricant.

…………………………………………………………………………………………………………….

…………………………………………………………………………………………………………….

…………………………………………………………………………………………………………….

………………………………………………………………………………………………………..

(b)        Suggest why boron nitride with structure B does not conduct electricity.

 

…………………………………………………………………………………………………………….

………………………………………………………………………………………………………..

 

……………………………………………………………………………………………………………

(c)        Suggest why boron nitride with structure B can be used in cutting tools and drill bits.

……………………………………………………………………………………………………………

……………………………………………………………………………………………………………

……………………………………………………………………………………………………….

 

  1. An impure sample of iron(II) sulphate was analysed by titration.

 

The sample was dissolved in 25.0 cm3 of dilute sulphuric acid and then titrated against 0.0400 mol/dm3 potassium dichromate(VI) solution.

 

19.0 cm3 of potassium dichromate(VI) solution was required to reach the end-point.

 

(a)        Calculate the number of moles of potassium dichromate(VI) used in the titration.

…………………………………. moles

 

 

(b)        One mole of potassium dichromate(VI) reacts with six moles of iron(II) ions.

Calculate the mass, in grams, of iron(II) ions in the sample analysed.

 

mass of iron(II) ions…………………………………. g

 

 

Miracle Learning Centre (O Level Chemistry Tuition/ IP Chemistry Tuition)

Did you answer the Secondary Chemistry Tuition Question correctly?

 

5.a. Soft / slide pass each other

 

  1. No mobile electrons / ions

 

  1. All atoms are strongly held together by covalent bonds, compact & closely packed, bonds between atoms are difficult to be broken

 

6.a. 0.00076 mol

 

  1. 0.255 g (3s.f.)

 

Learn from our Chemistry Tuition Question and Answer.

Miracle Learning Centre Call 6463 8756 or sms 8128 8342/9839 9908.

(Specialist in Science and Maths) for Primary, Secondary and JC levels.

Miracle Learning Centre specialises in Physics tuition, Chemistry tuition, Maths tuition and Science tuition Classes.